A narrow parallel incident beam of light falls from the left on a solid glass sphere at normal incidence. The radius of the sphere is R and its index of refraction is n = 1.52. Find the distance of the image from the right edge of teh sphere(adsbygoogle = window.adsbygoogle || []).push({});

Hint was to treat the sphere like a thin lens

Since this beam is parallel rays the object disatnce approaches infinity, and thus 1/o approaches zero.

also [tex] \frac{1}{f} = (n-1) \frac{2}{R} [/tex]

and [tex] \frac{1}{f} = \frac{1}{i} + \frac{1}{o} [/tex]

and since 1/o appraoches zero then focus distance = image distance = R/2(0.52). So tis means that the image will occur at the focus of the right edge but it will be a virtual image occuring isnide the sphere?? So what can be said about the orientation of thius image?

please help with this! Help would be greatly appreciated!

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# Homework Help: Find the distance of the image from the right edge of the sphere

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