Find the energy stored in a spring at .05m and .10m

  • Thread starter Thread starter davyvfr
  • Start date Start date
  • Tags Tags
    Energy Spring
AI Thread Summary
To find the energy stored in a spring at .05m and .10m with a spring constant of 67.21 N/m, the formula F = 1/2 kx^2 is used. The user expresses uncertainty about calculating the energy solely with the given distance and spring constant, noting that the provided graph only extends to 0.3m. The discussion emphasizes the need for clarity on how to apply the formula effectively. It highlights the importance of understanding the relationship between force, distance, and spring constant in determining energy storage. The conversation aims to resolve the calculation method for the specified distances.
davyvfr
Messages
5
Reaction score
0

Homework Statement


Find the energy stored in a spring when stretched .05m, and .10m. Spring Constant of 67.21 N/m.

(I am given a graph)


Homework Equations


F=1/2kx^2


The Attempt at a Solution


Ok, to find the energy stored I believe I am going to need the distance (.05m, and .10m) and the spring constant. Is there a way to calculate energy stored with just this? I am given a graph but the Force vs. Distance (in meters) only goes up to 0.3m so I can't rely on the graph just by looking at it.
 
Physics news on Phys.org
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top