Find the equation of motion for a fixed particle in a wave

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The discussion focuses on deriving the equation of motion for a fixed particle in a transverse traveling wave described by y(x,t)=0.6e^(2x-5t)cos(5t-2x). Part (a) confirms that the wave satisfies the one-dimensional wave equation and deduces the wave speed and direction of propagation. In part (b), the task is to use the previously calculated expressions for the second and first partial derivatives of y with respect to time to demonstrate that a + 10v + 50y = 0. The emphasis is on applying results from part (a) to complete the derivation efficiently. Understanding the relationship between the derivatives and the wave function is crucial for solving part (b).
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A transverse traveling wave is described by
y(x,t)=0.6e2x-5tcos(5t-2x)​
for x and y measured in cm and t in s
a) Show that y(x,t) satisfies the one-dimensional wave equation, and use this to deduce the wave speed. What is the direction of propagation?
b)USe the work from part (a) to show that the equation of motion for a particle at a fixed x is
a + 10v + 50 y = 0​

Note: a is the second partial derivitive of y w.r.t t, v is the first partial derivitive of y w.r.t. t.

I have done part a) fine but am at a complete loss as to what to do in part b), and it is only worth 2 marks compared to the 8 for part a)
 
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Basically they just want you to use your expressions for a=\frac{\partial^2 y}{\partial t^2}, and v=\frac{\partial y}{\partial t}...that you calculated in part (a) to show that a+10v+50y=0
 
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