Find the equation of the line through (-9, 2); perpendicular to y= -1

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Discussion Overview

The discussion revolves around finding the equation of a line that passes through the point (-9, 2) and is perpendicular to the line defined by the equation y = -1. The focus is on identifying the correct form of the equation and clarifying the concepts involved.

Discussion Character

  • Homework-related, Conceptual clarification

Main Points Raised

  • One participant asks for the slope of the line that is perpendicular to y = -1, indicating a need for clarification on the relationship between slopes of perpendicular lines.
  • Another participant expresses confusion about the problem, noting that they are struggling with the current unit.
  • There is a suggestion that the original poster may have made a typo regarding the line they intended to reference, with a specific alternative equation proposed.
  • A participant points out that the standard form for a line is typically Ax + By = C, contrasting it with the slope-intercept form mentioned by the original poster.
  • Discussion includes an explanation of what a horizontal line (y = k) looks like, which is relevant to understanding the context of the problem.

Areas of Agreement / Disagreement

Participants do not reach a consensus, as there is uncertainty about the original problem statement and potential typographical errors. Multiple viewpoints regarding the correct form of the equation and the nature of the line are presented.

Contextual Notes

There are limitations regarding the clarity of the original problem, including possible typographical errors and the definitions of the forms of equations being discussed.

bcm322
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Find the equation of the line through (-9, 2); perpendicular to y= -1.
Use standard form : y=mx+b
 
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Hello, and welcome to MHB! (Wave)

What will the slope of the requested line be?
 
That's all the information given for the homework problem.
I'm stuck on this unit :confused:
 
bcm322 said:
Find the equation of the line through (-9, 2); perpendicular to y= -1.
Use standard form : y=mx+b

Did you make a typo? Perhaps you mean the line $\color{black}y=\color{red}x\color{black}-1$, or something like that?
The answer to the problem as you type it cannot be put the standard form $y=mx+b$.
 
Olinguito said:
Did you make a typo? Perhaps you mean the line $\color{black}y=\color{red}x\color{black}-1$, or something like that?
The answer to the problem as you type it cannot be put the standard form $y=mx+b$.


Oops...I didn't catch that. Good eye! :)
 

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Okay, when we have a line of the form:

$$y=k$$

Where \(k\) is some real number, what does the graph of such a line look like?

By the way, standard form for a line is usually meant to be:

$$Ax+By=C$$

The form you cited initially is the slope-intercept form, and the line we're seeking cannot be written in that form, as noted by Olinguito.
 

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