MHB Find the equation of the line through (-9, 2); perpendicular to y= -1

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To find the equation of the line through the point (-9, 2) that is perpendicular to y = -1, it's important to recognize that y = -1 is a horizontal line. The slope of any line perpendicular to a horizontal line is undefined, indicating a vertical line. Therefore, the equation of the line through (-9, 2) is x = -9. The discussion clarifies the difference between standard form and slope-intercept form, emphasizing the appropriate representation for vertical lines.
bcm322
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Find the equation of the line through (-9, 2); perpendicular to y= -1.
Use standard form : y=mx+b
 
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Hello, and welcome to MHB! (Wave)

What will the slope of the requested line be?
 
That's all the information given for the homework problem.
I'm stuck on this unit :confused:
 
bcm322 said:
Find the equation of the line through (-9, 2); perpendicular to y= -1.
Use standard form : y=mx+b

Did you make a typo? Perhaps you mean the line $\color{black}y=\color{red}x\color{black}-1$, or something like that?
The answer to the problem as you type it cannot be put the standard form $y=mx+b$.
 
Olinguito said:
Did you make a typo? Perhaps you mean the line $\color{black}y=\color{red}x\color{black}-1$, or something like that?
The answer to the problem as you type it cannot be put the standard form $y=mx+b$.


Oops...I didn't catch that. Good eye! :)
 

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Okay, when we have a line of the form:

$$y=k$$

Where \(k\) is some real number, what does the graph of such a line look like?

By the way, standard form for a line is usually meant to be:

$$Ax+By=C$$

The form you cited initially is the slope-intercept form, and the line we're seeking cannot be written in that form, as noted by Olinguito.
 
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