Find the equation of the line with slope -1 that is tangent to the curve y=1/x-1
The Attempt at a Solution
Slope of -1 means y=-1x+k
-1x+k = 1/x-1
I don't know how to rearrange this into a quadratic equation so that I can solve this.
I know I use b^2-4ac=0 and substituting for a, b and c.... I'm just stuck on rearranging the equation into the form: ax^2+bx+c=0