Find the function of the form y = tan kx

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To find the function of the form y = tan kx that passes through the point (290 degrees, -1), the equation y = tan k(290 degrees) must be solved. The arctan(-1) gives -π/4, leading to the equation -π/4 = k(290 degrees). It's important to keep the units consistent, so if degrees are used on one side, they must be used on the other. The discussion highlights the need to divide rather than multiply to isolate k, leading to the correct function. The final function can be determined by correctly calculating k from the established relationship.
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Homework Statement



Find the function of the form y = tan kx that pass through (290 degrees, -1)

Homework Equations



y = tan kx

The Attempt at a Solution



y = tan kx
-1 = tan k(290 degrees)
arctan(-1) = k290 degrees
-pi/4 = K 290

I don't know where to go from here, or even if this is right...do I try to convert 290 to a rad approximation?? I'm doing this course online and they give very little explanation...Any help is much appreciated!
Thanks!
 
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Welcome to PF!

Hi Lepton_dyson! Welcome to PF! :wink:
Lepton_dyson said:
arctan(-1) = k290 degrees
-pi/4 = K 290

Make up your mind! :rolleyes:

If you have degrees on the RHS, you must have degrees (-45 of 'em) on the LHS also. :smile:
 


tiny-tim said:
Hi Lepton_dyson! Welcome to PF! :wink:


Make up your mind! :rolleyes:

If you have degrees on the RHS, you must have degrees (-45 of 'em) on the LHS also. :smile:

Thanks for the welcome!
Then I just multiply them? so -45(290) = -13050?
y = tan -13050 x -------I just didn't think that looked right...is it?

Thanks for the help!
 
Lepton_dyson said:
Then I just multiply them?!

divide :wink:

and conquer! :biggrin:​
 
tiny-tim said:
divide :wink:

and conquer! :biggrin:​

Cool thanks for your help!
 

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