Find the Intersection Point of a Line and Plane: Step by Step Guide

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To find the intersection point of the given line and plane, start by substituting the line's equations x = -4t + 4, y = -4t + 6, and z = 5t + 5 into the plane equation 4x - 2y + 6z = 78. This substitution will yield a linear equation in terms of t. Solve this equation for t, then use the value of t to calculate the corresponding x, y, and z coordinates from the line's equations. This process will provide the intersection point of the line and the plane. Following these steps will ensure the solution is accurate.
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coordinate help please :)

Hi i just got my home work but don't know where to start. Any help on this just to get me started would be great:) I want to make sure I am doing it right

Thank you


Work out the coordinates where this line meets this plane.

Line x = -4 t + 4, y = -4 t + 6, z = 5 t + 5 and plane 4 x - 2 y + 6 z = 78.
 
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Plug your expressions for x,y,z into the plane definition. You now have an equation (linear) for t. Solve for t and plug it into your x,y,z definitions for the line.
 
hey thank you for replying i will give that a go :)
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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