Find the Inverse of f(x)=3+x2+tan((πx)/2) for -1<x<1: Step-by-Step Guide

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To find the inverse of the function f(x) = 3 + x^2 + tan(πx/2) for -1 < x < 1, the focus is on determining f^-1(3). The discussion highlights the importance of correctly interpreting the function and using the definition of an inverse function. Participants emphasize the need to rearrange the equation to isolate x, leading to the condition x^2 + tan(πx/2) = 0. There is a reminder that users should engage with the problem actively rather than seeking complete solutions. The conversation underscores the value of showing work and asking for hints rather than direct answers.
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Homework Statement


f(x)=3+x2+tan((πx)/2) where -1<x<1...then find f^-1(3)



Homework Equations



y=3+x2+tan((πx)/2)

The Attempt at a Solution


i jave ried to solve first for x and then interchange the x and y,bu i am having problem with the trignometric identity used here...
 
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Just making sure:

Is it

f(x) = 3 + x^{2} + \tan{\frac{\pi x}{2}}

you mean?
 
yea...its tan((pi*x)/2)
 
And you're only looking for f^-1(3)? If so, it might be easier to use the definition of an inverse function: What do you know about f(x) if

f^{-1}(3) = x

EDIT: Sorry, made a small-ish error there : P
 
Last edited:
VICKZZA said:

Homework Statement


f(x)=3+x2+tan((πx)/2) where -1<x<1...then find f^-1(3)



Homework Equations



y=3+x2+tan((πx)/2)

The Attempt at a Solution


i jave ried to solve first for x and then interchange the x and y,bu i am having problem with the trignometric identity used here...

If x2 is supposed to be x2, then you need to write it properly. You can either use the "X2" button on the palette at the top of the input panel, or else write the standard text version x^2. Anyway, if f(x) = 3 you need x^2 + tan(pi*x/2) = 0. Can you see what x must be?

RGV
 
yea but can u show me the whole
process
 
VICKZZA said:
yea but can u show me the whole
process

Who are you responding to? By "u", do you mean "you"? Was your message a question? (It did not end in a question mark!)

If it was a question, I must say that the answer is NO. Read the Forum rules. We are not permitted to do your work for you; we can just give you hints, which has already been done. Now you need to show some of your own work. If you do that and are still stuck you can come back and ask more questions.

RGV
 
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