Find the largest δ that works .

  • Thread starter Thread starter -Dragoon-
  • Start date Start date
  • Tags Tags
    Works
-Dragoon-
Messages
308
Reaction score
7
Find the largest δ that "works".

Homework Statement


Find the largest δ that "works" for the given ϵ:
\displaystyle \lim_{x\to1}2x = 2; ϵ = 0.1


Homework Equations


N/A


The Attempt at a Solution


Given ϵ > 0, then:
if 0 < |x - 1| < δ then |2x - 2| < ϵ
ϵ = 0.1, so, |2x - 2| < 0.1
Now to establish the connection:
|2x - 2| => |2 (x - 1)| => |2||x - 1| => 2|x - 1|
Therefore: 2|x - 1| < ϵ => |x - 1| < \frac{ϵ}{2} => |x - 1| <\frac{0.1}{2} =>|x - 1| < 0.05. The largest value that "works" for δ is 0.05 since if:
0 < |x - 1| < 0.05 then |2x - 2| < 0.1

But, in my textbook, the answer is 2ϵ = 0.2 as the largest value that "works" for δ. So, I just wanted to know what I did wrong in my calculations as the book only shows the solution and not the work. Thanks in advance.
 
Physics news on Phys.org


I disagree with the textbook and I agree with you.
 


Dick said:
I disagree with the textbook and I agree with you.

I see. Thanks.

I never would have thought university textbooks ever made such errors, even though high school ones were rife with them.
 


Retribution said:
I see. Thanks.

I never would have thought university textbooks ever made such errors, even though high school ones were rife with them.

The aren't that uncommon even at the university level. The same people are writing the textbooks.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top