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Find the largest δ that "works".
Find the largest δ that "works" for the given ϵ:
\displaystyle \lim_{x\to1}2x = 2; ϵ = 0.1
N/A
Given ϵ > 0, then:
if 0 < |x - 1| < δ then |2x - 2| < ϵ
ϵ = 0.1, so, |2x - 2| < 0.1
Now to establish the connection:
|2x - 2| => |2 (x - 1)| => |2||x - 1| => 2|x - 1|
Therefore: 2|x - 1| < ϵ => |x - 1| < \frac{ϵ}{2} => |x - 1| <\frac{0.1}{2} =>|x - 1| < 0.05. The largest value that "works" for δ is 0.05 since if:
0 < |x - 1| < 0.05 then |2x - 2| < 0.1
But, in my textbook, the answer is 2ϵ = 0.2 as the largest value that "works" for δ. So, I just wanted to know what I did wrong in my calculations as the book only shows the solution and not the work. Thanks in advance.
Homework Statement
Find the largest δ that "works" for the given ϵ:
\displaystyle \lim_{x\to1}2x = 2; ϵ = 0.1
Homework Equations
N/A
The Attempt at a Solution
Given ϵ > 0, then:
if 0 < |x - 1| < δ then |2x - 2| < ϵ
ϵ = 0.1, so, |2x - 2| < 0.1
Now to establish the connection:
|2x - 2| => |2 (x - 1)| => |2||x - 1| => 2|x - 1|
Therefore: 2|x - 1| < ϵ => |x - 1| < \frac{ϵ}{2} => |x - 1| <\frac{0.1}{2} =>|x - 1| < 0.05. The largest value that "works" for δ is 0.05 since if:
0 < |x - 1| < 0.05 then |2x - 2| < 0.1
But, in my textbook, the answer is 2ϵ = 0.2 as the largest value that "works" for δ. So, I just wanted to know what I did wrong in my calculations as the book only shows the solution and not the work. Thanks in advance.