Find the Laurent Series for f(z)=1/(z(z-1)) Valid on 1<|z-1|<infinity

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Homework Statement


Find the Laurent series for f(z)=1/(z(z-1)) valid on 1<|z-1|<infinity


Homework Equations


1/(1+a)=1-a+a^2-a^3... where |a|<1
we are not supposed to use integrals for this problem

The Attempt at a Solution


I want 1/(z-1) to be in my final answer, so I have 1/(z(z-1))=(1/(z-1))(1/(z-1))(1/(1+1/(z-1))=(*)
I can then expand the last of the three terms in (*) as 1/(1-1/(z-1))=1-(z-1)^-1+(z-1)^-2 etc.
Is this right? can I then multiply it by the first two (multiplicative) terms in (*) to get an extra (z-1)^-2 in each term of the series
 
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Yes, that's right.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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