# Find the limit in question 7e and 7g?

1. Dec 12, 2013

### haha1234

How can I find the limit in question 7e and 7g?
Finding limits is difficult!

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2. Dec 12, 2013

### vanhees71

7e: I guess everything is within real calculus. Then you can argue that the sine is bound and thus the limit must be zero:
$$0 \leq |x \sin(1/x)| \leq |x| \rightarrow 0.$$

7g: Expanding $\sin(1/x)$ around $x \rightarrow \infty$ gives
$$x \sin(1/x)=x [1/x+\mathcal{O}(1/x^3)] \rightarrow 1.$$

3. Dec 12, 2013

### haha1234

How to derive this?