Find the magnetic field at the origin

[TSny]

Closer, but no cigar (yet).

 

[gkamal]

actually the -4.66x10^-5 is negative not positive i just edited it like 2 sec b4 ur reply i hope this was the mistake

 

[TSny]

actually the -4.66x10^-5 is negative not positive i just edited it like 2 sec b4 ur reply i hope this was the mistake

Yes, that was the mistake. So, your final answer is?

 

[gkamal]

-2.48x10^-5 T in the i direction and -4.66x10^-5 in the j direction

 

[TSny]

I think that's it. Be sure to include units and whatever else is required.

 

[gkamal]

Yes it is right but just to make sure the B of I3 becomes positive because it's value is negative and it is point in the -x , thus it would be point in the +x with a positive value since 2 negatives cancel right?

btw thank you so much for your help

 

[TSny]

Yes it is right but just to make sure the B of I3 becomes positive because it's value is negative and it is point in the -x , thus it would be point in the +x with a positive value since 2 negatives cancel right?

That's not how I think about it. The field $\vec{B}_3$ produced by $I_3$ is a vector. So, I would not refer to it as being positive or negative. It has a magnitude that is positive. (All vectors have positive magnitude, by definition.) However, when I draw the direction of $\vec{B}_3$ in a sketch using the right hand rule for magnetic fields, I can see that it points to the right. So, the x-component is positive. [Edited]

btw thank you so much for your help

You are welcome. Glad I could be of some help.