Find the minum pts. in a trig equation

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The discussion revolves around finding the maximum and minimum points of the trigonometric equation z = cos²θ - cosθ + 6. Initially, a minimum value of 5¾ was identified, but confusion arose regarding the correct equation and the maximum value. After correcting the equation to include a negative cosine, it was clarified that the maximum occurs when cos(θ) = -1, yielding a maximum value of 8. Participants emphasized the importance of accurately identifying the cosine values to determine both extrema. The conversation highlights the process of completing the square and the significance of understanding trigonometric properties in solving such equations.
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I have a trig equation with me

z=cos^2\theta+cos\theta+6

i am supposed to find the maximum and minimum points of z using completing the square.

I have found 5\frac{3}{4} as the minumum, but how do i go about finding the maximum?
 
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The maximum is easy: the largest cos(θ) can possibly be is 1. What does that tell you?
 
It should come up to 2n\pi,n\in\mathbb{Z} for the maximum.

Daniel.
 
Hold on a second.Shouldn't the minimum be 4...?

Daniel.
 
ohhh sorry people, real sorry,

the equation should be,

cos^2\theta-cos\theta+6

its a minus cosine theta. I could get the minumum 5 3/4 but when i use cos theta=1, i get 6, not 8, that's where my problem comes in.
 
Ah- then you want cos(θ)= -1! Try that.
 
HallsofIvy said:
Ah- then you want cos(θ)= -1! Try that.



ohhh thanks alot, that was useful !
 
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