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awillso
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Find the moment of inertia of the system
- Thread starter awillso
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AI Thread Summary
To find the moment of inertia of the system consisting of two rectangular objects, one must first understand the basic principles of moment of inertia and how to apply them to composite shapes. The moment of inertia can be calculated using the formula I = Σ(m * r²), where m is the mass and r is the distance from the axis of rotation. For axes A, B, and C, the distances will vary based on the orientation and position of the rectangles. It's essential to break down the problem by calculating the moment of inertia for each rectangle individually and then applying the parallel axis theorem if necessary. Understanding these concepts is crucial for solving the problem effectively.
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Hello!
I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below.
Here is how I wrote the condition of equilibrium forces:
$$
\begin{cases}
F_{g\parallel}=F_{t1}+F_{t2}, \\
F_{g\perp}=F_{r1}+F_{r2}
\end{cases}.
$$
On the other hand...
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