Find the Nth Term: Simplifying the Denominator

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    Simplifying Term
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The discussion focuses on finding the nth term of the series x/2 + (x^2)/3 + (x^3)/2^2 + (x^4)/3^2 + (x^5)/2^3. The numerator is identified as x^n, while the denominator presents challenges, with participants suggesting that the next term could be x^6/3^3. It is proposed that there may be separate formulas for even and odd degree terms in the series. One participant develops the series to express the nth term as x^(2n-1)/2^n + x^(2n)/3^n. Clarification is requested on the notation used in the final expression.
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Homework Statement



find the nth term

Homework Equations



x/2+(x^2)/3+(x^3)/2^2+(x^4)/3^2+(x^5)/2^3+...

The Attempt at a Solution



the numerator clearly is x^n but i have problems with the denominator
 
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i have many problems with this serie because of the denominator
 
mario mata said:

Homework Statement



find the nth term

Homework Equations



x/2+(x^2)/3+(x^3)/2^2+(x^4)/3^2+(x^5)/2^3+...

The Attempt at a Solution



the numerator clearly is x^n but i have problems with the denominator
It looks to me like the next term in the series will be x^6/3^3. If that's correct, then there will be two formulas for this series: one for the even degree terms and one for the odd degree terms.
 
thank a lot but i have the answer, it ocurred me take the fisrt two memebers and develop the serie, obtaining x^2n-1/2^n+x^2n/3^n as the nth term
 
mario mata said:
thank a lot but i have the answer, it ocurred me take the fisrt two memebers and develop the serie, obtaining x^2n-1/2^n+x^2n/3^n as the nth term

I can't even guess what you mean by this: x^2n-1/2^n+x^2n/3^n

Please use parentheses around the exponents and numerators and denominators of fractions.
 
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