Find the Nth Term: Simplifying the Denominator

  • Thread starter Thread starter mario mata
  • Start date Start date
  • Tags Tags
    Simplifying Term
Click For Summary

Homework Help Overview

The discussion revolves around finding the nth term of a series involving terms of the form x^n divided by varying denominators, specifically 2 and 3 raised to different powers. Participants express challenges particularly with the denominator's structure in the series.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants attempt to identify patterns in the series, noting the numerator as x^n. There are questions regarding the formulation of the denominator, with some suggesting that the next term may follow a specific pattern involving powers of 3. Others explore the possibility of separate formulas for even and odd terms.

Discussion Status

The discussion is ongoing, with some participants providing insights into their reasoning and attempts to derive the nth term. There is a mix of interpretations regarding the series' structure, and while some guidance has been shared, no consensus has been reached on the correct formulation.

Contextual Notes

Participants have noted difficulties with the series and have requested clarification on notation, particularly regarding the use of parentheses in mathematical expressions. There is an indication of homework constraints influencing the discussion.

mario mata
Messages
6
Reaction score
0

Homework Statement



find the nth term

Homework Equations



x/2+(x^2)/3+(x^3)/2^2+(x^4)/3^2+(x^5)/2^3+...

The Attempt at a Solution



the numerator clearly is x^n but i have problems with the denominator
 
Physics news on Phys.org
i have many problems with this serie because of the denominator
 
mario mata said:

Homework Statement



find the nth term

Homework Equations



x/2+(x^2)/3+(x^3)/2^2+(x^4)/3^2+(x^5)/2^3+...

The Attempt at a Solution



the numerator clearly is x^n but i have problems with the denominator
It looks to me like the next term in the series will be x^6/3^3. If that's correct, then there will be two formulas for this series: one for the even degree terms and one for the odd degree terms.
 
thank a lot but i have the answer, it ocurred me take the fisrt two memebers and develop the serie, obtaining x^2n-1/2^n+x^2n/3^n as the nth term
 
mario mata said:
thank a lot but i have the answer, it ocurred me take the fisrt two memebers and develop the serie, obtaining x^2n-1/2^n+x^2n/3^n as the nth term

I can't even guess what you mean by this: x^2n-1/2^n+x^2n/3^n

Please use parentheses around the exponents and numerators and denominators of fractions.
 

Similar threads

Replies
11
Views
3K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K