Find the Optimum Spot to Minimize Wave Action in Large Water Tank Experiment

AI Thread Summary
To minimize wave action in the large water tank experiment, one should stand at points where the distance from the two openings differs by half a wavelength, which is 1.5 m in this case. The relevant equations involve calculating the angles and positions based on the wavelength and distance between the openings. The user attempted to apply the formulas but was uncertain about the values for x(n) and L. The discussion highlights the concept of two-slit interference as key to identifying optimal standing positions. Understanding these principles is crucial for achieving minimal wave action.
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Homework Statement


In a large water tank experiment, water waves are generated with straight, parallel wave fronts, 3.00 m apart. The wave fronts pass through two openings 5.00 m apart in a long board. The end of the tank is 3.00 m beyond the board. Where would you stand, relative to the perpendicular bisector of the line between the openings, if you want to receive little or no wave action?

2. Homework Equations

[P(n)*S(1)] - [P(n)*S(2)] = (n - 1/2)*wavelength

sin ANGLE(n) = (n - 1/2)*wavelength/(distance between sources)

x(n) / L = (n - 1/2) * wavelength / (distance between sources)


The Attempt at a Solution


I tried using the third formula, allowing the n be 1, the wavelength 3.00 m and the distance between the two sources 5.00 m, but i don't know what value i should assign x(n) and L. I don't know if I'm doing the question right. Can anyone help?
 
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This sounds like 2 slit interference. The points of no wave motion would be the places where the distances from the slits differ by 1/2 wavelength..
 
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