Find the probability distribution

AI Thread Summary
The discussion revolves around finding the probability distribution for the number of defective bulbs in a sample of two from a box containing three defective bulbs out of ten. The user calculated the probabilities as 7/15 for zero defective bulbs, 1/15 for two defective bulbs, and 7/30 for one defective bulb, but identified the latter as incorrect. A response pointed out that the probabilities must sum to one and highlighted that the calculation for one defective bulb should account for both possible arrangements, thus doubling the probability. The user is encouraged to revise their calculations to ensure accuracy in the probability distribution.
Sucks@Physics
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Homework Statement



A box of 10 flashbublbs contains 3 defective bublbs. A random sample of 2 is selcted and tested. Let X be the radom variable associated with the number of defective bulbs in the sample.

A) Find the probability distribution of X.

B) Find the expected number of defective bulbs in a sample.

I did this problem, I got 7/15 probability of there being no defective light bulbs, 1/15 of there being 2, but I got 7/30 of there being 1. The 7/30 is wrong but I don't know where I'm going wrong, please give me some help. Thanks in advance.

Homework Equations






The Attempt at a Solution



7/10*6/9 = 7/15
7/10*3/9 = 7/30
3/10*7/9 = 1/15
 
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Sucks@Physics said:
7/10*6/9 = 7/15
7/10*3/9 = 7/30
3/10*7/9 = 1/15

Hi Sucks@Physics ! :smile:

(in the last line, you wrote a 7 instead of a 2 :wink:)

As you've probably noticed, the three probabilities should add up to 1.

Your 7/30 is the probability of the first one being defective, and the second one good … but you also need the probability of the first one being good, and the second one defective … that doubles it! :smile:
 
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