Let C be the curve of intersection of the cylinder x^2-2x+y^2 =3 and the plane z=y+1. Find the radius of the osculating circle of the curve C at point (1,2,3)
The Attempt at a Solution
I am not really sure how to start it...
i tried finding the point of intersection by setting y=0 and got z=1, x=3, but doesnt really make sense to me to do so. I also tried setting the equation to each other, but it doesnt seem to make sense too..
it would be appreciated if anyone can tell me how to begin and guide me through it
Thanks in advance