Find the size of force acting on the body

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To find the size of the force acting on a 50 kg body being pulled with an acceleration of 2 m/s² on a horizontal plane at a 30-degree angle, the friction coefficient is 0.2. The user attempted to apply Newton's second law and break down the forces into components along the x and y axes. They are uncertain whether the "size of the force acting on the body" refers to the horizontal component (Fx) or the vertical component (Fy). Clarification on this terminology is sought, as understanding the resultant force is crucial for solving the problem effectively. The discussion emphasizes the need for clear definitions in physics problems.
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Homework Statement


One body whit m=50kg is pulled whit a acceleration a=2m/s2 on an horizontal plane whit an unknow force F which is making whit the plane an angle of 30 degree
The friction coeficient betwen the body and plane is \mu=0.2.Find the size of the force F.

m=50kg
a=2m/s2
\mu=0.2
\alpha=30

I need to find the size of force acting on the body

http://img11.imageshack.us/img11/7561/61868200.png"

Homework Equations


The Attempt at a Solution


Well i tried to calculate the force whit Newton's formula F=m*a;
Then whit force compontents on Ox,Oy
Oy:N-G-Fy=0
Ox:Ff-Fx=m*a

But my question is "size of force acting on the body" is Fx?!or Fy?!
 
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Please post the full text of the problem.
 


sese said:
But my question is "size of force acting on the body" is Fx?!or Fy?!

Resultant.
 

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