Find the slope of the tangent line using a specific formula

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Homework Help Overview

The original poster is attempting to find the slope of the tangent line for the function g(x) = 3t - t² at the point (0,0) using a specific formula provided in their textbook. The formula involves the difference quotient, which is commonly used in calculus to determine derivatives.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the difference quotient and the correct evaluation of the function at specific points. There are attempts to simplify expressions and clarify misunderstandings regarding the substitution of variables.

Discussion Status

Some participants have provided guidance on correctly substituting values into the function and simplifying the expressions. There is an ongoing exploration of the algebraic steps involved, with participants questioning assumptions about the formula and its application.

Contextual Notes

There is a noted confusion regarding the application of the formula, particularly in relation to the function's variables and the simplification of terms. The original poster expresses uncertainty about the arithmetic and conceptual understanding of the derivative process.

Centurion1
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Homework Statement


Find the slope of the tangent line using a specific formula

g(x)=3t-t2

at (0,0)

Homework Equations



Im told to use this equation by the book
f(c+deltax) - f(c)
Deltax

The Attempt at a Solution


Everytime i plug it in by way of the books style i get 2c. and then you are supposed to plug in the x value which gives me 0. But the right answer is 3
 
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Perhaps if you show some of your algebra...
 
sorry.

yeah I am not so sure its an aritmetic mistake but a misunderatanding of how to do things. but following what the book said to do here goes,

f(c + deltax) - f(c)
delta x

((c + deltax)2 - 3t) - (c2 -3t) foil it out
delta x

2c(deltax) + (deltax)2 simplify
Delta x

and then my book gets rid of both of the delta x's
i assume by simplyfying and i can only assume the deltax2 by plugging in zero because the lim approaches 0


and i get the wrong answer because i end up with 2c (which the book says to do) and then plug in a point which is 0 and its supposed to end up being 3?
 
You're getting the wrong answer because [tex]f(c + \Delta x) \neq ( c + \Delta x )^2 - 3t[/tex]. You should think about why.
 
thats the problem the book gives an example for linear problems, eg y= x and parabolas, y=x^2

im not sure what to do with this?
 
This isn't anything that would be an example in a calculus book, because it's function evaluation. (Although it may be in one of the "introductory" sections.)

If you have a function f(t) what does [tex]f(c + \Delta x)[/tex] mean? It means everywhere in the definition of f that you see a t, you should put a [tex]c + \Delta x[/tex].
 
really? its in chapter two of my calculus book section 2.1 finding the slope for a tangent line.

so your saying it should look like

3(c + Delta x) - (c + Delta x)2

so

3c + 3Delta x - c2 + 2c(deltax) + (deltax)2

?
 
I know this problem is a calculus problem, I'm saying the issue you're having isn't a calculus issue, so it might not be addressed in the examples.

Yes. You need to put [tex]c + \Delta x[/tex] everywhere you see t. Now do some algebra to simplify...
 
oh okay i understand what your saying about what I am doing wrong. i realize that f(x) is meant to plugged in whenever you see x. but the formulas was throwing me off.

but is this over delta x like the equation?
 
  • #10
Yes, the definition of derivative stays the same.
 
  • #11
so you can cancel a single delta x right? what happens with the other delta x's i assume the best one to cancel is the 2c delta x

sorry i know I am making this harder than it should be...
 

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