Find the Solution for ∫√(1+u²) du | Boost Your Math Skills Now!

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\int\sqrt{1+u^{2}} du
 
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Little ant said:
\int\sqrt{1+u^{2}}du

can someone solve it?

Yes, but I'd rather I helped YOU solve it.

Try a substitution u=tan(\theta), du=sec^2(\theta) d\theta. It might not make this any easier, but it's the best method I can think of right now.
 
i tried it. but i didn't can
 
Well, you should get as your equation...

\int sec^3(\theta) d\theta

And from there it's a simple integration by parts, taking u=sec(\theta) and dv=sec^2(\theta).
 
Moderator's note: thread moved from Calculus & Analysis
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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