Find the tension in the two wires

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AI Thread Summary
The discussion revolves around calculating the tension in two wires supporting a 36 kg traffic light at specific angles. The user initially derived equations for tension (T1 and T2) but received incorrect results when submitting to a web platform. Feedback suggested a potential error in trigonometric functions, specifically that the sine and cosine values may have been swapped. After considering this advice, the user confirmed they resolved the issue. The conversation highlights the importance of correctly applying trigonometric principles in physics problems.
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Homework Statement


Find the tension in the two wires supporting the 36 kg traffic light shown in Fig. 12-57. (Assume that 1 = 52° and 2 = 38°.)

http://img15.imgspot.com/u/07/77/15/952alt.gif

Homework Equations


-T1cos(52)+T2cos(38)=m*g
T1sin(52)+T2sin(38)=0


The Attempt at a Solution



so I found T1=-T2sin(38)/sin(52)
and plugged into the first equation and got
[sin(38)*cos(52)/sin(52)+cos(38)]*T2=353.16
and got T2 = 278N
and T1=217N

but when I put it into the webassign it is wrong...
so what am I doing wrong?
 
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It would be useful if you presented the figure somehow.

You may want to check your trig, although I can't tell for sure.
 
i think the sins and cosines are reversed. The vertical weight mg is opposed by the sines of the respective tensions.
 
denverdoc is right. Just "swap" m*g and 0.
 
k thanks a lot got it :)
 
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