Find the value of a capacitor given percent of the initial value

AI Thread Summary
The problem involves calculating the value of a capacitor discharging through an 80.0-ohm resistor, where the discharge current drops to 23.0% of its initial value in 1.50 ms. The relationship between time, resistance, and capacitance is given by the equation t = RC. An initial calculation yielded a time constant RC of 6521.74, leading to a capacitor value of 81.5 μF. However, this result is incorrect, and further clarification is needed regarding the non-linear nature of the voltage versus time graph described by the equation v(t) = V_0e^(-t/RC).
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Homework Statement



A capacitor is discharged through an 80.0 ohm resistor. The discharge current decreases to 23.0% of its initial value in 1.50ms .

What is the value of the capacitor?

Homework Equations



t=RC

The Attempt at a Solution



1500 μs = 0.23 RC
RC= 6521.74

C= 6521.74/R

C= 6521.74/80 = 81.5 μF


This is not correct... Please help! It's due within the next thirty minutes!
 
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The voltage vs time graph is not linear.
$$v(t)=V_0e^{-t/RC}$$
 
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