Find the Value of x: Math Problem

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The equation (6^x) + 1 = (2^x) + 2 requires finding the value of x, which is not straightforward. The exact solution is irrational and cannot be expressed in a simple closed form. Numerical approximations, such as 0.4895363, can be obtained, but they are not exact. Tools like the Newton-Raphson Method can assist in finding these approximations. The discussion emphasizes the complexity of the problem and the need for proper methods to solve it.
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(6^x)+1=(2^x)+2
please find the value of x , thanks
 
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fku4321 said:
(6^x)+1=(2^x)+2
please find the value of x , thanks

This should really be in the homework section, but what have you tried?
 


fku4321 said:
(6^x)+1=(2^x)+2
please find the value of x , thanks

Hello.

Please show working. Thanks.
 


this isn't homework
 


about 0.5, comparing √6 to √2
 


It doesn't matter, it's a homework style question. You can add why you need it solved etc, and then maybe we'll give a bit of leeway.
 


my friend asked me this question and i solved for a whole day still can't can get the exact answer 0.48
 


The problem is that 0.48 isn't the exact answer. It's only a numerical approximation.
A better approximation is 0.4895363 but even this isn't exact. The exact answer is irrational and doesn't have a closed form solution in terms of surds and logs and whatnot.

If you just wanted to find a numerical approximation however, there are quite a few tools you can use, such as the Newton-Raphson Method.
 


thanks for your explanation ,it really helps me a lot
 
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