Find the vertical and horizontal asymptotes.

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The discussion focuses on finding the vertical and horizontal asymptotes of the function f(x) = earctan x. The original poster, Bob, initially graphed the function and estimated the horizontal asymptotes around y = 0.20788 and y = 4.81048. However, he was guided to calculate the limits of arctan(x) as x approaches infinity and negative infinity instead of relying on the calculator. The correct horizontal asymptotes were identified as y = π/2 and y = -π/2. The conversation emphasizes understanding the mathematical definition of arctan for accurate results.
bobraymund
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Homework Statement



Find the vertical and horizontal asymptotes.

Homework Equations



f(x) = earctan x

The Attempt at a Solution



Honestly, I am pretty stumped on this problem. I have graphed it on my calculator and messed around a bit, it seems that the horizontal asymptotes are around y = 0.20788 and y = 4.81048. Or something along those lines.

Any help would be greatly appreciated.

Thanks,
Bob
 
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You'll need to figure out the limit of arctan(x) as x->infinity and (-infinity). Put the calculator away and remember the definition of arctan.
 
Dick said:
You'll need to figure out the limit of arctan(x) as x->infinity and (-infinity). Put the calculator away and remember the definition of arctan.

Oh, ha ha. Wow, how embarrassing.

It's just epi/2 and e-pi/2.

Thanks, heh heh.

-bob
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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