Find the zeroes of r. What to do when it is a multiple of theta?

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To find the zeros of the equation 5 + 10cos(2θ) = 0, first isolate cos(2θ) to get cos(2θ) = -1/2. The next step involves determining the angles where the cosine function equals -1/2, which occurs at 2θ = 2π/3 + 2kπ and 2θ = 4π/3 + 2kπ, where k is any integer. After finding 2θ, divide by 2 to solve for θ. Consulting a trigonometry textbook can provide additional examples and methods for solving such equations involving angle multiples.
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I understand what to do when theta is by itself such as r=5+10cos(theta) but what if you have the same equation, and it is (2theta) I am on taptalk by the way.
 
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Tyrion101 said:
I understand what to do when theta is by itself such as r=5+10cos(theta) but what if you have the same equation, and it is (2theta) I am on taptalk by the way.
What have you tried?
In essence, you're trying to solve the equation ##5 + 10\cos(2\theta) = 0##.
 
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Well if it were without the 2*theta I'd set it equal to 0, like you did, and solve for cos(theta). Well anyway without the 2 you turn the equation into cos=-1/2, would I just multiply -1/2 by 2? Or would I add 2pi or something?
 
Solve for 2*theta. Solve for theta from that.
 
Tyrion101 said:
Well if it were without the 2*theta I'd set it equal to 0, like you did, and solve for cos(theta). Well anyway without the 2 you turn the equation into cos=-1/2, would I just multiply -1/2 by 2? Or would I add 2pi or something?
You took a trig class, right? Do you still have your textbook? If so, there should be numerous examples of solving trig equations, including ones that involve the sine or cosine (or other trig function) of angle multiples.
 
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