Find this limit without L'Hopital's Rule

htoor9
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Homework Statement



L'Hopital's rule does not help with this limit. Find it some other way. lim (squarert(x)/squarert(sinx)) as x -> 0+

Homework Equations



None?

The Attempt at a Solution



The only way I can think of solving this is by using L'Hopital's rule...but it obviously isn't working. How else can I find this limit?
 
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htoor9 said:

Homework Statement



L'Hopital's rule does not help with this limit. Find it some other way. lim (squarert(x)/squarert(sinx)) as x -> 0+

Homework Equations



None?
There are at least a couple of limits that are relevant.
\lim_{x \to 0} \frac{sin(x)}{x} = 1
\lim_{x \to a} f(g(x)) = f(\lim_{x \to a} g(x)), \text{provided that f is continuous at g(a)}
htoor9 said:

The Attempt at a Solution



The only way I can think of solving this is by using L'Hopital's rule...but it obviously isn't working. How else can I find this limit?
 
Expand sin x as a power series...
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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