Find Torque of Circle Homework Solution

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To find the net torque of a circular object with inner and outer radii of 12 cm and 20 cm, three forces are applied: 11 N, 28 N at 29 degrees below the horizontal, and 16 N. The initial calculation of net torque was incorrectly computed as 2.04 Nm. The force of 28 N is not perpendicular to the radius of the smaller circle, which affects the torque calculation. Correct torque must account for the angle of the applied force, indicating that the approach needs adjustment to accurately determine the net torque. The solution requires re-evaluating the torque contributions from each force based on their respective angles.
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Homework Statement



A Circular-shaped object has an inner radius of 12 cm and an outer radius of 20 cm. Three forces (acting perpendicular to the axis of rotation) of magnitudes 11 N, 28N, and 16 N act on the object. The force of magnitude 28 N acts 29 degrees below the horizontal. Find the magnitude of the net torque through the center of the object.

torque.jpg


Homework Equations

The Attempt at a Solution


So I added all the torques together.
-(.12*28)+(.2*11)+(.2*16)=2.04
which came out to 2.04 Nm. Am I right? When I put it, it said it was wrong...
 
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Hi minikk, welcome to PF.
From the diagram I feel that the force 28 N may not be perpendicular to the radius of the smaller circle. That is why they have given the angle of the force below the horizon.
 

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