Find total ionic (balanced equation) for this particular reaction.

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The discussion focuses on finding the total ionic equation for the reaction between calcium hydroxide and phosphoric acid in aqueous solution. The balanced equation is presented as 3Ca(OH)2 + 2H3PO4 → Ca3(PO4)2 + 6H2O. The participant struggles with determining which compounds to dissociate based on solubility rules, noting that calcium hydroxide dissociates fully while phosphoric acid only partially dissociates. Ultimately, it is clarified that both phosphoric acid and calcium phosphate should be considered insoluble for the purpose of the total ionic equation. The participant successfully resolves the confusion by applying these insights.
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Homework Statement



Find the total ionic (balanced) equation of the reaction of calcium hydroxide and phosphoric acid in aqueous solution.

Homework Equations



Solubility rules

The Attempt at a Solution



First, I balanced the reaction.
3Ca(OH)2 + 2H3PO4 --> Ca3(PO4)2 + 6H2O
The part I'm stuck at is I don't know what to break up and what to leave. I know the solubility rules, but for some reason I keep getting this question wrong.

I know that Ca(OH)2 can break up into 3Ca2+ + 6OH-
But is that the only one that breaks up?
I looked it up and I'm getting mixed results. Please help me if you can. Thanks in advance.
 
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No idea what the correct answer is, as unfortunately it depends on what the teacher had on mind :frown:

Calcium hydroxide is weakly soluble (so mostly present as a solid), but it is a strong base (so it is 100% dissociated).

Phosphoric acid is a weak acid, so in typical solution it will be dissociated only partially, and only the first proton will be dissociated in substantial amounts (for example in 1M solution about 8%), yet it can react all the way down to PO43-.

Apparently you are expected to ignore some of these information and give answer based on some general (but not always correct) rules.
 
Thank you so much. I figured it out. They wanted me to look as phosphoric acid and calcium phosphate, both as insoluble. Thanks again!
 
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