Find Unit Vectors for f(x,y) w/ D_uf=0

Cpt Qwark
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Homework Statement


For f(x,y)=x^2-xy+y^2 and the vector u=i+j.
ii)Find two unit vectors such D_vf=0

Homework Equations


N/A.

The Attempt at a Solution


Not sure if relevant but the previous questions were asking for the unit vector u - which I got \hat{u}=\frac{1}{\sqrt{2}}(i+j) for the maximum value of D_uf which was \sqrt{2}.
 
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The directional derivative is defined as
D_{v}f = \nabla f \cdot \mathbf{v}
Your task is to find two vectors \mathbf{v} such that D_{v}f = 0.
 
Cpt Qwark said:

Homework Statement


For f(x,y)=x^2-xy+y^2 and the vector u=i+j.
ii)Find two unit vectors such D_vf=0
This problem doesn't have anything to do with the vector "u". Why is that given? D_vf is the dot product of the gradient, \nabla f, and a unit vector in the same direction as vector v. Since you want that to be 0, you are looking for two unit vectors perpendicular to \nabla f.

2. Homework Equations
N/A.

The Attempt at a Solution


Not sure if relevant but the previous questions were asking for the unit vector u - which I got \hat{u}=\frac{1}{\sqrt{2}}(i+j) for the maximum value of D_uf which was \sqrt{2}.
So "u" was used in previous questions?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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