Find Upper Bound for \| A \| - Homework Statement

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Homework Statement



assume that x and y are vectors, and A is a matrix.

can anyone kindly help me to find an upper bound C w.r.t \| A \| s.t.

\| x-Ay \| \leq C \cdot \| x-y\|
 
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Some quick-and-dirty trial gives me
C = sup( ||(A - I) v|| )
where I is the identity matrix and the supremum is taken over all vectors v.

I wonder if you can do any better, without more information on A.
 
Thank you for ur kind help. if all the entries of A is between 0 and 1, can we get a nicer upper bound ?
 
CompuChip said:
Some quick-and-dirty trial gives me
C = sup( ||(A - I) v|| )
where I is the identity matrix and the supremum is taken over all vectors v.

I wonder if you can do any better, without more information on A.

Could u show me any hints about ur estimate for C.

I only figure out that \|x-Ay\|=\|(x-Ax)+(Ax-Ay)\|\leq\|I-A\| \|x\|+\|A\| \|x-y\|

I don't know how to continue... could anyone kindly give me more hints ?
 
Last edited:
I did
|| x - A y|| = || (x - y) + (y - Ay) ||

But when all entries of A are between 0 and 1, then you can define ||A|| by
|| A || = max(i, j)( |Aij| )
and use that to get a better estimate.
 
CompuChip said:
I did


But when all entries of A are between 0 and 1, then you can define ||A|| by
|| A || = max(i, j)( |Aij| )
and use that to get a better estimate.

if || x - A y|| = || (x - y) + (y - Ay) ||,
then || x - A y|| <= || (x - y) || + || (y - Ay) ||,

but how could u find that C = sup |x-Ax| for all x ?

notice that my esitmate is C*||x-y||
 
can someone give me a hand?
 
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