Find [v]s with Basis S={t+1,t-1} in P_1: v=5t-2"

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Homework Statement



Let v=5t-2,S={v_1,v_2 }={t+1,t-1} is a basis of P_1 where P_1 is a vector space of all polynomials of degree ≤1. What is [v]s? Let v=5t-2,S={v_1,v_2 }={t+1,t-1} is a basis of P_1 where P_1 is a vector space of all polynomials of degree ≤1. What is [v]s?

2. The attempt at a solution
I need your help to provide me the correct way of putting the answers together, like the one in the answer scheme. Thanks in advance!
 
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v=[5t-2]=a[t+1]+b[t-1]

(1st) at+bt=5t
(2nd) a-b=-2
v=3⁄2 v_1+7⁄2 v_2
[v]_s=[■(3⁄2@7⁄2)]
is this correct?
 
hadizainud said:
v=[5t-2]=a[t+1]+b[t-1]

(1st) at+bt=5t
(2nd) a-b=-2
v=3⁄2 v_1+7⁄2 v_2
Looks good. I'm not exactly sure what the following notation means, though:
[v]_s=[■(3⁄2@7⁄2)]
is this correct?
 
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