- #51

- 111

- 21

Methinks the image in #48 is a good answer to the problem statement in #19 (also an image ).

Whether it's still correct can be checked 'easily':

and all that for 3 points ....

- ##{dv\over dx} = 0\ \ ## at ##\ \ x_0 = - {mg\over k} ##
- substitute ##\omega =\sqrt{k\over m}, \ \ \xi = x_0-x, \ \ v = ## .... oh, well, maybe not that easy ...

Makes me curious to see parts b) and c)

##\ ##

I think 48 is the derivative of the solution?

we solved a and b almost I think. a asks to set up the differential equation. b asks to solve it.

I haven't looked at what c and d is yet, but it seems not to difficult, c) asks you to graph the function v(x) in an x-v-diagramm.

And d finally asks you for the deviation (*Auslenkung, I don't quite know what that word in german means actually) and the speed of the mass when the spring is pulled 20 cm up or down.

I think it just means plug in 0.2 for x and state the value. so v(0.2).

a, b and c each give you 3 points, d 1 point.

I'll figure out Latex too! :-) It doesn't let me edit the previous post anymore, I think I did it too many times. But next chance I get.