Find Values of a and b for Perpendicular Vectors

noahsdev
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Homework Statement



If \underline{v} = a\underline{i} + 2\underline{j} + 3\underline{k} and \underline{w} = 2\underline{i} +b\underline{j} - \underline{k} and |\underline{v}| = |\underline{w}|, find the values of a and b so that \underline{v} and \underline{w} are perpendicular.

If v = ai+3j+3k and w = 2i+bj-k and |v| = |w|, find the values of a and b so that v and w are perpendicular.

Homework Equations



\underline{a} - (\underline{a}.\underline{\hat{b}})\underline{\hat{b}}

The Attempt at a Solution


sqrt(a2+13) = sqrt(b2+5)

I am so confused right now. Any help would be great. Thanks
 
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noahsdev said:

Homework Statement



If \underline{v} = a\underline{i} + 2\underline{j} + 3\underline{k} and \underline{w} = 2\underline{i} +b\underline{j} - \underline{k} and |\underline{v}| = |\underline{w}|, find the values of a and b so that \underline{v} and \underline{w} are perpendicular.


Homework Equations



\underline{a} - (\underline{a}.\underline{\hat{b}})\underline{\hat{b}}

The Attempt at a Solution


sqrt(a2+13) = sqrt(b2+5)

I am so confused right now. Any help would be great. Thanks

That's one equation. To get another equation, use the requirement that u and v be perpendicular. Hint: There is a simple operation that can be used to determine whether two vectors are perpendicular.
 
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Mark44 said:
That's one equation. To get another equation, use the requirement that u and v be perpendicular. Hint: There is a simple operation that can be used to determine whether two vectors are perpendicular.

Thanks, haha, so simple. I'm so angry at myself now. :)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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