Find Work Done by Engine in One Propeller Rev - 171 hp, 2310 RPM, 527.612 N*m

  • Thread starter Thread starter ACLerok
  • Start date Start date
  • Tags Tags
    Dynamics
AI Thread Summary
To find the work done by the engine in one revolution of the propeller, the power output of 171 hp is converted to watts, resulting in 746 J/s. The rotational speed of the propeller is 2310 revolutions per minute, which can be converted to revolutions per second for calculations. Using the relationship between power, torque, and work, the formula W = τθ can be applied, where τ is torque and θ is the angle in radians. The discussion emphasizes that both methods of calculation should yield the same result for work done per revolution. Understanding these conversions and formulas is essential for accurate calculations in aviation mechanics.
ACLerok
Messages
194
Reaction score
0
The engine of an aircraft propeller delivers an amount of power 171. hp to the propeller at a rotational velocity of 2310 rev/min. I found the torque produced to be 527.612 N*m
How can i find the work done by the engine in one rev of the propeller?
 
Physics news on Phys.org
Power is the rate at which work is done.

171 hp = 746 W = 746 J/s

You have how many revs / s ?

(J/s)/(r/s) = J/r
 
use this equation to find the work done: W = τθ (it's the rotational analog to W = Fd; realize that it's still a dot product, but we've simplified already)
 
Touche, gnome.

ACLerok: you should get the same answer either way.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top