Find z for ez=1+i√3: Solution Explained

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SUMMARY

The discussion centers on solving the equation \( e^z = 1 + i\sqrt{3} \). The solution involves expressing the complex number \( 1 + i\sqrt{3} \) in polar form as \( r e^{i\theta} \), where \( r \) is the modulus and \( \theta \) is the argument. Participants emphasize the importance of converting the equation into the form \( e^x e^{iy} = r e^{i\theta} \) to find the values of \( z \). This method clarifies the relationship between the exponential and trigonometric representations of complex numbers.

PREREQUISITES
  • Understanding of complex numbers and their polar representation
  • Familiarity with Euler's formula \( e^{i\theta} = \cos(\theta) + i\sin(\theta) \)
  • Knowledge of the modulus and argument of complex numbers
  • Basic skills in solving exponential equations
NEXT STEPS
  • Learn how to calculate the modulus and argument of complex numbers
  • Study Euler's formula in depth for better comprehension of complex exponentials
  • Explore the properties of logarithms in the context of complex numbers
  • Practice solving similar equations involving complex exponentials
USEFUL FOR

Students studying complex analysis, mathematicians interested in exponential functions, and anyone looking to enhance their understanding of complex number equations.

alexcc17
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Homework Statement


Find all values of z such that ez=1+i√3

Homework Equations


The Attempt at a Solution


I have no idea how to do this. I was going to start with ez=exeiy and try to figure something out from that, but I'm not seeing anything. I checked the solution shown below, but I'm really confused as to how they went from the equation given to the first step. An explanation would be really helpful.
 

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alexcc17 said:

Homework Statement


Find all values of z such that ez=1+i√3


Homework Equations





The Attempt at a Solution


I have no idea how to do this. I was going to start with ez=exeiy and try to figure something out from that, but I'm not seeing anything. I checked the solution shown below, but I'm really confused as to how they went from the equation given to the first step. An explanation would be really helpful.

If you write ##1 + i \sqrt{3} = r e^{i \theta}## (where you can easily figure out ##r## and ##\theta##) then the equation is ##e^{z} \equiv e^x e^{iy} = r e^{i \theta}##.
 

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