Finding A Function From A Power Series

Bashyboy
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Homework Statement


Find the sum of the series and its radius of convergence:

\sum_{n=1}^{\infty} (-1)^{n+1}\frac{(x-1)^n}{n}


Homework Equations





The Attempt at a Solution


I found the radius of convergence, but I wasn't sure how to find the sum of the power series.
 
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Bashyboy said:

Homework Statement


Find the sum of the series and its radius of convergence:

\sum_{n=1}^{\infty} (-1)^{n+1}\frac{(x-1)^n}{n}


Homework Equations





The Attempt at a Solution


I found the radius of convergence, but I wasn't sure how to find the sum of the power series.

Hint: If you call that series f(x), what is f'(x)?
 
Would it be f'(x) = \sum_{n=0}^{\infty} (-1)^{n+1}(x-1)^{n-1}?
 
Bashyboy said:
Would it be f'(x) = \sum_{n=0}^{\infty} (-1)^{n+1}(x-1)^{n-1}?

Yes. And do you recognize what kind of series that is?
 
If you distribute the (-1)^(n+1) to the (x-1)^(n-1) would it be a geometric series?
 
Bashyboy said:
Would it be f'(x) = \sum_{n=0}^{\infty} (-1)^{n+1}(x-1)^{n-1}?

Bashyboy said:
If you distribute the (-1)^(n+1) to the (x-1)^(n-1) would it be a geometric series?

Do you really have to ask? What do you think? Why? Show us what you would do if it is.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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