Finding a Linear Transformation with specific domail and range

apdixon
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Hey, i have an assignment in MATLAB class which is
Let L be a linear transformation such that
L(1)=(2 -1)'
L(1-x)=(1 0)'
L(1+x^2)=(1 1)'
L(1+x^3)=(1 2)'
Determine a matrix in domain such that with the canonical in range, the matrix that represents L has two null columns.

I don't know exactly what they're asking me to find. I found L by solving LP=A, being A the transformed matrix [2 1 1 1;-1 0 1 2], and P the matrix P=[1 1 1 1;0 -1 0 0;0 0 1 0;0 0 0 1]. But it doesn't have two null columns, and it was too easy to find to be true. Pleaaaase help!
 
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You found the matrix for L where the basis for the domain is {1, x, x2, x3} (which is reflected in how you constructed P). If you use a different basis for the domain, you'll get a different matrix that represents the linear transformation L. The problem is asking you to find a basis for the domain so that the matrix has two null columns.
 
Thank you! I found the Ker for A=[2 1 1 1; -1 0 1 2], then constructed a matrix F with the Ker in the first two columns and (0100)' and (1000)' in the next two so that i had a matrix of 4x4 and then multiplied A*F. I found L=
0 0 1 2
0 0 0 -1 .
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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