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FaraDazed
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Homework Statement
A block of mass of 60kg is at rest on a smooth horizontal surface and is then pushed with a constant force of 126N for 10 seconds.
Ignoring friction and air resistance;
A. calculate the acceleration of the block during the 10 seconds
B. calculate the velocity after 10 seconds.
Homework Equations
F=ma
Impulse=Force x time
Ns=mv-mu
v=u+at?
The Attempt at a Solution
Part A:
My first attempt A:
126x10=1260
1260/60 = 21ms^2
My second attempt after think i made it more complicated is:
F=ma
126=60xa
a=126/60=2.1ms^2Part B:
First attempt
Ns=mv-mu
1260=(60xv)-(60-0)
1260+60=60xv
1320=60xv
v=1320/60= 22ms
Second Attempt:
126x10=1260
1260/30=10.5
Further Discussion:
I am assuming from the question that when they say "calculate the velocity after 10 seconds" they mean the final velocity (v)? If so then couldn't I use the motion equation v=u+at to find Part B if I know that Part A is right?
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