Finding an integral given two other integrals?

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To find the integral from 4 to 16, the properties of integrals are applied, specifically that integral(4 to 16) equals integral(1 to 16) minus integral(1 to 4). Given the values, integral(1 to 16) is 13 and integral(1 to 4) is 7. Therefore, the calculation is 13 - 7, resulting in an integral from 4 to 16 of 6. The conclusion confirms that the solution is correct.
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Homework Statement



It is given that

integral(1 to 2) g(x)dx=22
integral (1 to 4) g(x)dx=7
integral (1 to 16) g(x)dx=13

Find integral (4 to 16)


Homework Equations



Using properties of integrals, integral(4 to 16)= integral(1 to 16) - integral(1 to 4)


The Attempt at a Solution



So, you can ignore the in integral (1 to 2) since it is not in the interval you need to solve for.

Integral(1 to 16) - integral(1 to 4) = 13-7 =6

The integral from (4 to 16) = 6

Am I correct?
 
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JessicaJ283782 said:

Homework Statement



It is given that

integral(1 to 2) g(x)dx=22
integral (1 to 4) g(x)dx=7
integral (1 to 16) g(x)dx=13

Find integral (4 to 16)


Homework Equations



Using properties of integrals, integral(4 to 16)= integral(1 to 16) - integral(1 to 4)


The Attempt at a Solution



So, you can ignore the in integral (1 to 2) since it is not in the interval you need to solve for.

Integral(1 to 16) - integral(1 to 4) = 13-7 =6

The integral from (4 to 16) = 6

Am I correct?

Yes, you are.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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