Finding area-FTC (is it right?)

  • Thread starter maks4
  • Start date
  • #1
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1. The question is:
Find the area between the x-axis and the curve y=sinx on [0, PI]



2. And i think i did it right but i just want to make sure...
So an anti derivative of sinx is = -cosx
Evaluating comes to = -cos PI - (-cos 0) which comes out to 1+1=2


This is right, right?

And a second question as well

2. Find the area bounded by the curves y = x^2 and y = x^3 on the interval [0,1]
Ok here is the solution
2ept284.jpg


What i don't understand here is, shouldn't (1/4 * x^4) be 0? Aren't you replacing the x with a 0 and doesn't the rest of it become 0? It just seems like only the 1 is evaluated on both of them and that's how it comes to 1/3 - 1/4...i don't understand how it came to that. (sorry if this is obvious but i can't see it)
 
Last edited:

Answers and Replies

  • #2
rock.freak667
Homework Helper
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EDIT:
Looks correct.
 
  • #3
264
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You forgot units squared, but yeah it looks right.
 
  • #4
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^^Thanks both of you. But what do you mean i forgot units squared?
 
  • #5
264
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When stating an area, you're 'suppsed' to put units^2 after your constant.
 
  • #6
36
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Oh right, thanks!
 
  • #7
36
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Never mind about the second question i figured it out...:shy:
 

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