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**1. The question is:**

Find the area between the x-axis and the curve y=sinx on [0, PI]

Find the area between the x-axis and the curve y=sinx on [0, PI]

**2. And i think i did it right but i just want to make sure...**

So an anti derivative of sinx is = -cosx

Evaluating comes to = -cos PI - (-cos 0) which comes out to 1+1=2

So an anti derivative of sinx is = -cosx

Evaluating comes to = -cos PI - (-cos 0) which comes out to 1+1=2

This is right, right?

And a second question as well

**2. Find the area bounded by the curves y = x^2 and y = x^3 on the interval [0,1]**

Ok here is the solution

What i don't understand here is, shouldn't (1/4 * x^4) be 0? Aren't you replacing the x with a 0 and doesn't the rest of it become 0? It just seems like only the 1 is evaluated on both of them and that's how it comes to 1/3 - 1/4...i don't understand how it came to that. (sorry if this is obvious but i can't see it)

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