Finding charge on conducting sphere

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SUMMARY

The discussion focuses on calculating the charge and charge density on the surface of a conducting sphere with a radius of 0.15 meters and a potential of 200 volts. The surface area of the sphere is established as 0.28274 square meters. To find the total charge (Q), the relationship between charge density (σ) and surface area (A) is utilized, where σ = Q/A. By rearranging this formula, the charge can be determined as Q = σ * A.

PREREQUISITES
  • Understanding of electrostatics and charge distribution
  • Familiarity with the concept of electric potential
  • Knowledge of surface area calculations for spheres
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the relationship between electric potential and charge on conductors
  • Learn about Gauss's Law and its application to spherical conductors
  • Explore the concept of surface charge density in electrostatics
  • Investigate the effects of varying potential on charge distribution
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Students and professionals in physics, electrical engineering, and anyone interested in electrostatics and charge calculations on conductors.

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I need to find the charge and charge density on the surface of a conducting sphere of radius r=0.15m and of a potential of V=200V.

I know the surface charge density, which is Q/A. The surface area is 0.28274, but I can't find the charge.
 
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