Finding COM, and inertia my answers don't make sense?

  • Thread starter Thread starter amyparker30
  • Start date Start date
  • Tags Tags
    Inertia
AI Thread Summary
The discussion centers on finding the center of mass (COM) and rotational inertia of a given object with specified masses. The initial calculations presented by the user were incorrect, prompting a request for clarification. Key points include the need to calculate the COM in the x, y, and z directions using the respective distances for each mass. Additionally, the rotational inertia should be calculated using the correct formulas, emphasizing the importance of understanding the underlying principles. The conversation highlights the necessity of systematic problem-solving and the application of physics equations to arrive at accurate results.
amyparker30
Messages
13
Reaction score
0
Finding COM, and inertia please help my answers don't make sense??

Homework Statement



Find the center of mass of the object shown in the figure below?

LINK TO FIGURE:
http://s1168.photobucket.com/albums/r497/amy_parker1/?action=view&current=Untitled.jpg

1. Find the center of mass of the object shown in the figure below.

2. Calculate the rotational inertia of the object about the x-axis.

3. From this value, deduce the rotational inertia of the object about an axis parallel to the x-axis, and going through the center of mass.

m1=2.5kg , m2=5kg, m3=2.5kg , m4=5kg

Homework Equations



COM

Inertia?

The Attempt at a Solution



my answers don't make sense

for COM I got 2
 
Physics news on Phys.org


Hi amyparker30! Where are your answers? Where is your working?
 


ok, my answers are totaly wrong but for COM 1 got (2(2.5+5+2.5+5))/15 = 2

ICOM=Rotational Inertia = 2^2(2.5+5+5+2.5) = 60

i bet these are 100% wrong what should I do, my teacher wouldn't help me and the people from class just skipped this question :(
 


Ok first you need to understand the COM formula and see how it works. Basically you need to specify a coordinate to tell where the COM is. That means you need to find the center of mass in the x direction, y direction, and z direction of the system or object.
So we start by separating everything in components( x, y and z). Let's do the x direction first.

We let d_{nx} represent the distance in the x direction for each particle (n=1,2,3,4)
Then
X_{com} = \frac{m_2 d_{2x}+m_3 d_{3x} + m_1 d_{1x}+m_4 d_{4x}}{M}
where M is the total mass. Note that
d_{2x}=d_{1x}=0
and
d_{3x}=d_{4x}=2 m

Similarly for y:
Y_{com} = \frac{m_2 d_{2y}+m_3 d_{3y} + m_1 d_{1y}+m_4 d_{4y}}{M}
Note that
d_{2y}=d_{3y}=0
d_{1y}=d_{4y} = 2 m

Similarly for z:
Z_{com} = \frac{m_2 d_{2z}+m_3 d_{3z} + m_1 d_{1z}+m_4 d_{4z}}{M}
But Note that
d_{1z} = d_{2z} = d_{3z} = d_{4z} = 0
then
Z_{com} = 0

Then at the end you get the COM to be at (X_{com},Y_{com},Z_{com})

Now try to plug in the numbers and see what you get. (Easy! =))

Do the same thing for the next part (moment of inertia), first understand the formula/equation and just follow it slowly.
 
Last edited:


I think the first part of this question would be a good one for a multiple choice test. :smile:

By symmetry, the CoM of the two equal masses m1 and m2 is mid-way between them. Likewise, the CoM of the equal mass pair m3 and m4 is mid-way between m3 and m4. And you wouldn't believe our luck :wink: but those two CoM locations coincide!
1OqIj.gif


So that surely must be the CoM for the 4 bodies.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top