Finding cross product of two vectors a,b

AI Thread Summary
The discussion focuses on calculating the scalar and vector products of two vectors with magnitudes of 17 units and 7.4 units, separated by an angle of 27 degrees. The scalar product is determined using the formula a*b = abcos(theta), resulting in a value of approximately 112.089. For the vector product, the correct formula is A x B = absin(theta), leading to the conclusion that the magnitude is 17(7.4)(sin(27)). The right-hand rule is mentioned for determining the direction of the vector product, which points along the z-axis. Understanding the geometric implications of these calculations is noted as a point of confusion.
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Homework Statement


A vector of magnitude 17 units and another vector of magnitude 7.4 units differ in directions by 27°. Find (a) the scalar product of the two vectors and (b) the magnitude of the vector product ×.

Homework Equations



Right-hand rule, a*b=abcos(theta), A x B= absin(theta)

The Attempt at a Solution


Dot product => a*b= (17)(7.4)(cos(27))= 112.089

Just not quite sure on how to do the cross product. The right hand rule gives me a vector pointing straight up the z axis when sweeping into b but not sure what values to plug into absin(theta) Thanks.
 
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Hm. It seems the answer is just 17(7.4)(sin(27). Not sure geometrically why this is the case though.
 
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