Finding Current and Potential Difference in a LCR Circuit

In summary, the problem described involves a circuit with parallel L and R components and a capacitor, a switch, and a battery source. The switch is closed and the capacitor is uncharged, resulting in all currents being equal to 0. The problem lies in finding the correct equations for current, with the given values of E = 12 V and R = 1.37 ohms, but lacking the value for L. The attempted solution involved searching for equations online, but has not been successful so far.
  • #1
mgrphysics
1
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Homework Statement


There is a circuit, with the L and R in parallel and then there is a capacitor as well. There is a switch and a battery source. The E = 12 V and R is 1.37ohms. The switch is closed and the capacitor is uncharged and all currents are 0


Homework Equations


That's what I am having problems with, I though the equations for current was:
L: E/R (1-(e^-t/(L/R)))
C: E/R (e^-t/(RC))
R: V/R

But I was not given the L, so I don't really think those are the right forumlas, and I don't know where to try and look for the formulas.
 
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  • #2
The Attempt at a SolutionI have tried to look for equations online, but I think I am going about it wrong. I can't seem to find the right equations.
 
  • #3


As a scientist, it is important to understand and apply the correct equations and principles when analyzing a circuit. In this case, the circuit is a LCR (inductor-capacitor-resistor) circuit with a battery source and a switch. The goal is to find the current and potential difference in the circuit.

Firstly, it is important to note that the values given are not sufficient to accurately solve for the current and potential difference. In order to do so, we would need to know the values of the inductor (L) and the capacitor (C). Without these values, it is not possible to use the equations you have provided.

The correct equations for current and potential difference in a LCR circuit are as follows:

Current (I) = V/R (1-e^(-t/RC))
Potential difference (V) = E - IR
where:
V = battery voltage
R = resistance
C = capacitance
t = time

It is also important to note that in this circuit, the switch is closed and the capacitor is uncharged, so the initial conditions for the equations would be V=0 and I=0.

To find the values of L and C, we would need to either be given those values or measure them using appropriate equipment. Once we have those values, we can solve for the current and potential difference at different time intervals.

In conclusion, in order to accurately find the current and potential difference in a LCR circuit, we need to have all the necessary values and use the correct equations. It is also important to understand the initial conditions and the role of each component in the circuit.
 

1. How do I calculate current and potential difference in a LCR circuit?

The current in a LCR circuit can be calculated using Ohm's law, which states that current (I) is equal to the potential difference (V) divided by the resistance (R). The potential difference, or voltage, in a LCR circuit can be calculated by multiplying the current (I) by the total resistance (R) in the circuit.

2. What is the difference between current and potential difference in a LCR circuit?

Current refers to the flow of electric charge through a circuit, while potential difference refers to the difference in electric potential between two points in the circuit. In a LCR circuit, current is affected by the resistance, while potential difference is affected by both the resistance and the inductance and capacitance of the circuit.

3. How does the inductance and capacitance affect current and potential difference in a LCR circuit?

The inductance and capacitance of a circuit can affect both the current and potential difference. Inductance causes a delay in the current flow, leading to a lag in the current compared to the voltage. Capacitance, on the other hand, causes a phase difference between the current and voltage, resulting in a leading or lagging current.

4. What are some common methods for measuring current and potential difference in a LCR circuit?

Current can be measured using an ammeter, which is connected in series with the circuit. Potential difference can be measured using a voltmeter, which is connected in parallel with the component or circuit being measured. Other methods include using an oscilloscope or a multimeter.

5. How can I improve the accuracy of my measurements in a LCR circuit?

To improve the accuracy of measurements in a LCR circuit, it is important to use high-quality and properly calibrated equipment. It is also helpful to reduce external interference by shielding the circuit and using precision components. Additionally, taking multiple measurements and calculating an average can help to reduce errors in the readings.

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