Finding distance of a block with an unattached spring

  • Thread starter Thread starter Robertoalva
  • Start date Start date
  • Tags Tags
    Block Spring
AI Thread Summary
A 9 kg block is compressed against a spring with a spring constant of 118 N/m and then released on a horizontal plane with a coefficient of kinetic friction of 0.67. The block moves a distance D before stopping, influenced by the energy stored in the spring and the work done against friction. The kinetic energy (KE) and potential energy (U) of the spring can be used to calculate the initial velocity of the block after release. The total mechanical energy is equal to the sum of KE and U, minus the work done by friction. The discussion emphasizes using energy methods to find the distance the block travels before coming to a stop.
Robertoalva
Messages
140
Reaction score
0
1. A 9 kg block is pushed by an external force against a spring with spring constant 118 N/m until the spring is compressed by 2.1 m from its uncompressed length (x= 0). The block rests on a horizontal plane that has a coefficient of kinetic friction of 0.67 but is NOT attached to the spring. After all the external forces are removed (so the compressed spring releases the mass) how far D along the plane will the block move before coming to a stop? The acceleration due to gravity is 9.8 m/s^2.



Homework Equations


U=1/2kx^2
KE= 1/2mv^2


The Attempt at a Solution



If I'm not mistaken, I have to use one of the acceleration formulas,but first i have to find the velocity of the block with the kinetic energy formula
 
Physics news on Phys.org
I suggest using energy methods to solve this.
 
so, i just use KE and U? and how will it be then?
 
Robertoalva said:
so, i just use KE and U?
Don't forget the work done against friction.
 
so then it will be, KE+U-W=Total Energy ?
 
Robertoalva said:
so then it will be, KE+U-W=Total Energy ?
I'd put it this way. At any moment, the total mechanical energy = KE + U. The change in the total mechanical energy will equal the work done by friction.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top