Finding Distance Traveled with Varying Acceleration

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The discussion focuses on determining how the power delivered by a motor varies with time when driving a body with constant force. It is established that under ideal conditions, where friction is negligible, the power P varies linearly with time t, expressed as P = (F^2/m)t. Additionally, when analyzing a point with varying acceleration, the need for integration to find velocity and distance is emphasized, as the standard kinematic equations apply only to constant acceleration. Participants express confusion over the application of these equations in their calculations. The conversation highlights the importance of understanding the relationship between force, velocity, and power in physics problems involving varying conditions.
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Homework Statement



a motor drives a body along a straight line with a constant force. The power P delivered by the motor must vary with time t according to?
where t is time and conditions are ideal

Homework Equations



P = F v
x=vt

The Attempt at a Solution


according to me answer comes as t-1 but as you know that's not the answer is t just that
 
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Your question is unclear.
 
vipulgoyal said:
a motor drives a body along a straight line with a constant force. The power P delivered by the motor must vary with time t according to?
where t is time and conditions are ideal

P=Fv, where F is constant, so P must vary with time according to v.
 
I like Serena said:
P=Fv, where F is constant, so P must vary with time according to v.

i felt the same when i read the question
 
vipulgoyal said:

Homework Statement



a point initially at rest moves along x-axis its accelaration varies with time as a= 6t+5 if it starts from the origin the distance covered in 2s is

Homework Equations




s= ut +1/2at2

The Attempt at a Solution



ijus tried put the values of different variable in the equation but the answer doesnot come that way is their any prob with it??
 
vipulgoyal said:
i felt the same when i read the question

Actually we can say a bit more.
Under ideal conditions I assume the friction is zero.

That means:

a = \frac F m

v = a t = \frac F m t

P = F v = \frac {F^2} m t

So P varies linearly with t.
 
vipulgoyal said:

Homework Statement



a point initially at rest moves along x-axis its accelaration varies with time as a= 6t+5 if it starts from the origin the distance covered in 2s is

Homework Equations



s= ut +1/2at2

The Attempt at a Solution



ijus tried put the values of different variable in the equation but the answer does not come that way is their any prob with it??

Your equation only holds when a is constant.

You need the following equations:

\begin{equation}v(t) = \int_0^t a(t) dt \label{eq:a_integral}\end{equation}<br /> \begin{equation}s(t) = \int_0^t v(t) dt \label{eq:v_integral}\end{equation}
 
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