Finding Distance Traveled with Varying Acceleration

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Homework Help Overview

The discussion revolves around the relationship between power, force, and distance traveled by a body under varying acceleration. Participants are exploring how power delivered by a motor changes over time when a constant force is applied, as well as the implications of varying acceleration on distance calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between power and velocity, questioning how power varies with time under constant force. There is also an exploration of the equations of motion when acceleration is not constant, with attempts to apply standard kinematic equations.

Discussion Status

Some participants have provided insights into the relationship between power and time, suggesting that power varies linearly with time under ideal conditions. Others are questioning the application of kinematic equations when acceleration is variable, indicating a lack of consensus on the correct approach to the problem.

Contextual Notes

There are indications of confusion regarding the application of equations for variable acceleration and the conditions under which certain equations are valid. Participants are also considering assumptions such as the absence of friction in their analyses.

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Homework Statement



a motor drives a body along a straight line with a constant force. The power P delivered by the motor must vary with time t according to?
where t is time and conditions are ideal

Homework Equations



P = F v
x=vt

The Attempt at a Solution


according to me answer comes as t-1 but as you know that's not the answer is t just that
 
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Your question is unclear.
 
vipulgoyal said:
a motor drives a body along a straight line with a constant force. The power P delivered by the motor must vary with time t according to?
where t is time and conditions are ideal

P=Fv, where F is constant, so P must vary with time according to v.
 
I like Serena said:
P=Fv, where F is constant, so P must vary with time according to v.

i felt the same when i read the question
 
vipulgoyal said:

Homework Statement



a point initially at rest moves along x-axis its accelaration varies with time as a= 6t+5 if it starts from the origin the distance covered in 2s is

Homework Equations




s= ut +1/2at2

The Attempt at a Solution



ijus tried put the values of different variable in the equation but the answer doesnot come that way is their any prob with it??
 
vipulgoyal said:
i felt the same when i read the question

Actually we can say a bit more.
Under ideal conditions I assume the friction is zero.

That means:

[tex]a = \frac F m[/tex]

[tex]v = a t = \frac F m t[/tex]

[tex]P = F v = \frac {F^2} m t[/tex]

So P varies linearly with t.
 
vipulgoyal said:

Homework Statement



a point initially at rest moves along x-axis its accelaration varies with time as a= 6t+5 if it starts from the origin the distance covered in 2s is

Homework Equations



s= ut +1/2at2

The Attempt at a Solution



ijus tried put the values of different variable in the equation but the answer does not come that way is their any prob with it??

Your equation only holds when a is constant.

You need the following equations:

[tex]\begin{equation}v(t) = \int_0^t a(t) dt \label{eq:a_integral}\end{equation}<br /> \begin{equation}s(t) = \int_0^t v(t) dt \label{eq:v_integral}\end{equation}[/tex]
 

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