Finding domain with e functions help

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The discussion focuses on finding the domain of the function 1/[e^(x+y)-3]. The key condition derived is that e^(x+y) must be greater than or equal to 3, which leads to the conclusion that x+y cannot equal ln(3). Participants emphasize the importance of avoiding division by zero, which occurs when e^(x+y) equals 3. The method of separating variables using the property e^(x+y) = e^x * e^y is acknowledged but deemed less useful for this specific problem.

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bart11
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I'm asked to find the domain of 1/[e^(x+y)-3]

Which means I'm solving for e^(x+y)>=3

But how would I go about solving this?
 
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e^(x+y) = e^y*e^x
 
pickslides said:
e^(x+y) = e^y*e^x

Thanks! But hmm, I'm still confused
 
This is supposed to help you separate x & y so you can find a function in the form of y = f(x) and find the domain from there.
 
bart11 said:
I'm asked to find the domain of 1/[e^(x+y)-3]

Which means I'm solving for e^(x+y)>=3

But how would I go about solving this?
The only possible "difficulty" with that is that you cannot divide by 0. That, in turn, means that e^{x+y} cannot be equal to 3. So, what can x+ y not be equal to?

(To solve e^x= a, take the natural logarithm of both sides.)

Pickslide's observation that e^{x+y}= e^xe^y is true but I don't believe using that is particularly useful here.
 
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