Finding Eigenvectors & Stabilizing 0,0 in System Stability

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For the system

\dot{x}=y2
\dot{y}=x2

Both the eigenvalues are zero. How do I
find the eigenvectors so that I can sketch
the phase portrait and how do I classify
the stability of the fixed point (0,0)?
 
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Well, obviously, both x^2 and y^2 are positive for all non-zero x and y so (0, 0) is unstable.
 
Yes, that is true. Thank you. How do I find the eigenvectors though?
 
It is not necessary to compute eigenvectors. This system is Hamiltonian (conservative). On dividing one equation by the other you get
\begin{equation}
\frac{dx}{dy} = \frac{y^2}{x^2}
\end{equation}
Separating variables and integrating you find the Hamiltonian
\begin{equation}
H(x,y) = \frac{1}{3} (x^3-y^3)
\end{equation}
The level sets \begin{equation}H = constant\end{equation} define the phase portrait.
 
oh my god, that make life so easy. Thank you!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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