Equation of a Circle Passing Through Given Points

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To find the equation of a circle that passes through the y-axis and x-axis and the point (8, -1), it is essential to understand that the circle is tangent to these axes. The equation should be in the form (x-h)² + (y-k)² = r², where (h, k) is the center and r is the radius. The radius can be determined as either 8.5 or 0.5, depending on the center's position. The discussion emphasizes using geometric principles and the Pythagorean theorem to derive the solution. Understanding the tangential relationship to the axes is crucial for solving the problem correctly.
furtivefelon
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hi, this isn't really a physics problem, more of a math problem, however, i can't find a math forum.. so i thought i'd put it here :D

your given that a circle passes through y-axis adn x-axis, also the circle passes through the points (8, -1).. find the equation of the circle, reminded that the equation should be in the following form: (x-h)^2+(y-k)^2=r^2

i have no idea how i should approach this problem, thanks a lot for your help :P
 
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furtivefelon said:
your given that a circle passes through y-axis adn x-axis, also the circle passes through the points (8, -1)..

What are the other points?
 
that's teh whole question.. that's suppose to be the hardest problem on the sheet, and since there are no any other point, i can't figure it out :|
 
What do you mean my passes through "y" & "x" axis...?Shouldn't it be the other way around...?:wink: Actually,i think they mean that the circle is tangent to those lines...

I found the radius to be either 8.5,or 0.5.You decide which value is correct...

Daniel.
 
mmm.. yes, it indeed is tangent to the x/y axis.. can you tell me how you got it? i care more about the process than the result :D thank you very much!
 
Draw a circle & use geometry in a pythagoreic triangle...

Daniel.
 

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